2x^2-6x=6x2-8x

Solution for 2x^2-6x=6x2-8x equation:

2x^2-6x=6x^2-8x

We move all terms to the left:

2x^2-6x-(6x^2-8x)=0

We get rid of parentheses

2x^2-6x^2-6x+8x=0

We add all the numbers together, and all the variables

-4x^2+2x=0

a = -4; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-4)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-4}=\frac{-4}{-8}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-4}=\frac{0}{-8}
=0
$